Hi All,

I have searched the web, but was unable to find a solution to the following:

I have three address-lists configured, each driving workstations through three different WAN ports.

I just need a simple quick way (without using the GUI, so through the terminal) to find out to which list any particular IP belongs.. In other words, somthing like:

/ip firewall address-list get list where address=192.168.x.x

and as a return to the above, just spit out: list1, list2 or list3.

hope this makes sense, but let me know if you have any suggestions.
Thanks,
Kenneth

Although it's normally not a good idea to spoon feed such scripts, I've been wondering on what kind of sample scripts to work on that I might practice scripting with... so thank you for providing me with this opportunity, although I also kind'a feel gulty of taking it away from you.

Here's a script that does just what you said:只是取代first line with whichever IP you need. You could declare that variable as a global one, but in that case, you'd have to set it right before running the script.

Hi Again,

I know it has been a while since you posted this, and realise that I never gave credit where it was due.

Therefore, just wanted to say thanks and confirm that your script worked BRILLIANTLY.

I really appreciated your input and it really did save me a lot of time and effort.

Thanks Again.
K

Wow - this does the same thing..

Great stuff.. thanks Blake.

k.

Code:Select all

:put [/ip firewall address-list get value-name=list [find address=192.168.x.x]]

Hi, i got some error if there is the IP on multiple list,
> :put [/ip firewall address-list get value-name=list [find address=1.1.1.1]]
invalid internal item number
how i can see all of list that contains the ip?
please help me, thx before